16-25w^2=0

Solution for 16-25w^2=0 equation:

16-25w^2=0

a = -25; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-25)·16
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-25}=\frac{-40}{-50}
=4/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-25}=\frac{40}{-50}
=-4/5
$